Image 1 Caption: The pressure curves of the classical ideal gas (see also Wikipedia: Ideal gas law) and ideal quantum gases (i.e., the Fermi gas and the Bose gas) as functions of temperature (i.e., Kelvin temperature) for a fixed particle density. The ideal gases are for the case of non-relativistic limit (i.e., they are consist of massive particles moving at velocities asymptotically close to zero relative to the vacuum light speed c = 2.99792458*10**8 m/s ≅ 3*10**8 m/s = 3*10**5 km/s ≅ 1 ft/ns) in (3-dimensional physical) space.
"The plot has been scaled in a way that the free particle degeneracy factors, densities, masses, etc. are all factored out and irrelevant." (Slightly edited.)
Features:
All the gases have an equation of state (EOS): i.e., a formula relating thermodynamic variables. Almost always by equation of state (EOS), one means a pressure law.
This pressure law is usually known as the ideal gas law P = (N/V)kT.
The ideal gas law is probably the simplest of all laws relating thermodynamic variables: i.e., equations of state (EOS).
The ideal gas law is often an excellent emergent theory: i.e., it is an exact limiting behavior that is so closely approached by actual gases in the right limit that in many cases discrepancies are unobservably small. Of course, we need other pressure laws where the ideal gas law fails: for example and most importantly, those for the Fermi gas and the Bose gas.
The discrepancy from ideal gas law P = (N/V)kT is negligible for sufficiently high temperature.
Note the degeneracy pressure is nonzero at absolute zero T = 0 K.
Note absolute zero T = 0 K case is an ideal limit that CANNOT be reached practically---but it can be approached very closely experimentally and in some astrophysical systems.
We will NOT describe the Bose-Einstein condensate here, but we note that as the pressure asymptotically goes to zero as temperature goes to absolute zero T = 0 K.
At absolute zero T = 0 K, all the bosons are in the Bose-Einstein condensate.????
Note again, absolute zero T = 0 K case is an ideal limit that CANNOT be reached practically---but it can be approached very closely experimentally and in some astrophysical systems.
For more on
white dwarf
pressure law,
see White dwarf file:
white_dwarf_mass_radius_relation.html.
Note the
Earth equatorial radius R_eq_⊕ = 6378.1370 km
and
solar radius R_☉ = 6.957*10**5 km = 109.1 R_eq_⊕ = 4.650*10**(-3) AU.
The failure
degenerate electron gas pressure
at the Chandrasekhar mass
leads to a collapse in which the
electrons and
protons
combine to make neutrons
which have the
degenerate neutron gas pressure.
This pressure
will sustain the collapsing white dwarf
as a neutron star (typical radius 10 km,
typical mass 1.4 M_☉).
In fact, neutron stars mostly
form from
core collapse supernovae
which form from
stars of the
mass
8
M_☉
to of order 20
M_☉ on the
main sequence
and NOT from collapsing
white dwarfs (which happen rarely).
Actually,
neutron stars
have an upper mass the
Tolman-Oppenheimer-Volkoff mass
which is analogous to the
Chandrasekhar mass.
The value of the
Tolman-Oppenheimer-Volkoff mass
is thought to be in the range 2
to 3
M_☉.
The uncertainty in the value
is due to uncertainty
in the nuclear matter
equation of state (EOS)
and the uncertainty
in observational constraints.
If a neutron star undergoes
mass accretion from a
close binary companion
and reaches the
Tolman-Oppenheimer-Volkoff mass,
it will collapse to being a
stellar mass black hole.
In fact, stellar mass black holes
mostly form from
core collapse supernovae
which form from
stars of ⪆
of order 20
M_☉ on the
main sequence
and NOT from collapsing
neutron stars due
mass accretion
(which happen rarely).
Many stellar mass black holes
probably form from
neutron star mergers.
The
neutron star mergers usually
occur for neutron star
binary systems that inspiral
to merger by losing orbital
energy in the
form of gravitational waves.
The vertical axis
is labeled P for power,
but F for flux
is choice of yours truly.
Yours truly uses P for
pressure in this figure.
But to flux
is proportional to the
pressure of the
photon gas that
makes up the flux: i.e.,
However, it is DISTINCT from
the Bose gas shown
in Image 1.
That Bose gas
is for non-relativistic
massive particles.
Photons
are massless particles
that always move at the
vacuum light speed c = 2.99792458*10**8 m/s
(exact by definition) ≅ 3*10**8 m/s = 3*10**5 km/s ≅ 1 ft/ns,
and so are always
extremely relativistic.
Being
massless particles
implies an infinite
Bose-Einstein condensate critical temperature.
The upshot is that
blackbody radiation
NEVER behaves like an
classical ideal gas
as the Bose gas
in Image 1 does
asymptotically as
temperature grows large.
Thus,
blackbody radiation pressure
grows as T**4,
and so is proportional to the
Stefan-Boltzmann law
flux
shown in Image 3 (as mentioned above),
where the vertical axis
should be F for flux to be consistent
with this figure.
Donald Clayton (1983, p. 155--165)
and Phil Armitage (2003)
give introductions to the basics of pressure
in stars.
M_ch = (1.45620... M_☉)/[(μ_e/2)**2]
(Wikipedia: Chandrasekhar limit:
Physics), where μ_e
is the mean molecular mass per electron
which approximately obeys the formula
μ_e ≅ 2/(1+X) ,
where X is the mass fraction
of hydrogen (H, Z=1)
(e.g., Cl-84).
For white dwarfs, X ≅ 0.
      P ∝ F    .
     
F = σT4   ,
where F is flux in
units of
watts
(i.e., joules per
second) per
meter squared,
the
Stefan-Boltzmann constant
σ = (5.67037441918442...)*10**(-8) W/*m**2/K**4 (exact)
(see NIST:
Fundamental Physical Constants --- Complete Listing 2018 CODATA adjustment),
and T is temperature
on the Kelvin scale.
     
P = (1/3)aT4 ,
where
radiation constant
a = (4σ/c) = (7.56573325028000...)*10**(-16) J/*m**3/K**4 (exact)
(see also
Wikipedia:
Photon gas: Thermodynamics of a black body photon gas;
Hyperphysics: Radiation Energy Density).
For important example,
blackbody radiation pressure
is important in massive
stars where it adds to the
ideal gas law pressure provided by
baryonic matter
(with usually approximately the
cosmic composition:
hydrogen (H, Z=1) ∼ 73 %,
helium-4 (He-4, Z=2) ∼ 25 %,
metals of order 2 %).
To illustrate this: