Caption: Kepler's 3rd law illustrated.
Features:
P_years**2 = R_AU**3 ,where AU stands for astronomical unit (AU) ≡ 1.49597870700*10**11 m ≅ 1.496*10**11 m. Of course, for the Earth, we have 1 = 1 since the natural units are natural for us Earthlings.
P = [(2π)/sqrt[G(M+m)]]*R**(3/2) ≅ [(2π)/sqrt[GM]]*R**(3/2) for m << M ,gravitational constant G = 6.67430(15)*10**(-11) (MKS units), M is the mass of the larger spherically symmetric astro-body, and m is the smaller spherically symmetric astro-body. In natural units, the second version of the above formula becomes
P_years**2 = [1/sqrt(M/M_☉)]R_AU**3 ,where the solar mass M_☉ = 1.98855*10**30 kg.