PHY 182, Spring Semester 2002
Homework #5: Temperature
(chapter 21)
Exercise 8:
U(0°C) = 0 mV
U(510°C) = 28.0 mV
è T = (510°C/28.0mV) U
For U = 10.2 mV: T = (510°C/28.0mV)
10.2 mV = 186 °C
Exercise 22:
La: length of side
a
Lb: length of side
b
ΔLa = α
La ΔT
ΔLb = α
Lb ΔT
ΔA ≈ ΔLa
* Lb + ΔLb * La = α La Lb
ΔT + α Lb La ΔT = 2 α A ΔT
q.e.d.
Exercise 33:
α(brass) = 1.9 * 10-5 K-1 (from
Table 21-3, p. 486)
ΔL/L = α*ΔT =
1.9 * 10-5 K-1 * 20 K = 3.8*10-4
Simple Pendulum: period T = 2π(L/g)1/2
è ΔT/T
= ½ ΔL/L = ½*3.8*10-4 =
1.9*10-4 = 0.68 s/h
Problem 4:
Δp = 120 mm Hg for ΔT = 100 K
è Δp/ΔT = 120 mm Hg
/ 100 K
ΔT = (100K/120 mmHg) * Δp
For the unknown temperature: Δp = ± 90 mm Hg (not further specified)
ΔT = (100K/120 mmHg) *
(± 90 mm Hg) = ± 75 K
è The temperatures differ by 75 K, i. e. the
unknown temperature is 273 K ± 75 K = 198 K or 348 K.